d) access Participate in the Sanfoundry Certification contest to get free Certificate of Merit. If a page number is not found in the TLB, then it is known as a ____________ The questions asked in this NET practice paper are from various previous year papers. Which algorithm of disk scheduling selects the request with the least seek time from the current head positions? c) restriction on page visibility b) has data in it View Answer, 7. This protection bit can be checked to verify that no writes are being made to a read-only page. d) user programs can implement dynamic loading without any special support from hardware or operating system The main purpose of memory protection is to prevent a process from accessing memory that has not been allocated to it. The required to access a page in secondary memory is equal to 100 ns. A solution to the problem of external fragmentation is : The …………….. policy segments the disks request queue into sub queues of the length N. The operating system and the other processes are protected from being modified by an already running process because : Data are allocated to disks in the RAID at the. Normally, these bits are kept in the page table. Here you can access and discuss Multiple choice questions and answers for various compitative exams and interviews. When the valid – invalid bit is set to valid, it means that the associated page ____________ 0.0. star. b) a two level paging algorithm star. a) 3.0 ns © 2011-2020 Sanfoundry. Protection. Explanation: Memory protection in a paged environment is accomplished by protection bits that are associated with each frame. View Answer, 5. In paged memory systems, if the page size is increased, then the internal fragmentation generally ____________ Protection … b) address space identifier d) constant Attempt a small test to analyze your preparation level. Operating System Objective type Questions and Answers. How is memory protection accomplished in a paged memory environment? a) miss ratio a) error c) TLB hit To practice all areas of Operating System for Quizzes, here is complete set on 1000+ Multiple Choice Questions and Answers on Operating System. Each entry in a translation lookaside buffer (TLB) consists of ____________ a) not to page a) address space locator One bit can define a page to be read-write or read-only. b) restricted access rights to users c) address process identifier Memory protection in a paged environment is accomplished by protection bits associated with each frame. Practice test for UGC NET Computer Science Paper. d) All of the mentioned This set of Operating System Quiz focuses on “Paging – 2”. A directory of Objective Type Questions covering all the Computer Science subjects. c) remains constant Memory protection in a paged environment is accomplished by _____ a) protection algorithm with each page b) restricted access rights to users c) restriction on page visibility d) protection bit with each page View Answer View Answer, 11. b) Buffer miss c) miss percent 1. One bit can define a page to be read-write or read-only. The average time required to access a page is? c) the page table itself The percentage of times a page number is found in the TLB is known as ____________ Questions from Previous year GATE question papers, UGC NET Previous year questions and practice sets. Illegal addresses are trapped using the _____ bit. The time required to access a page in primary memory is 10 ns. All Rights Reserved. b) 68.0 ns b) value c) valid – invalid View Answer, 4. star. a) becomes less These bits are kept in the page table. d) protection bit with each page. a) special support from hardware is required d) none of the mentioned c) special support from both hardware and operating system is essential Memory protection in a paged environment is accomplished by : RAID 0 has no redundancy and is sometimes nicknamed as, The memory allocation scheme subject to “external” fragmentation is. When the valid - invalid bit is set to valid, it means that the associated page : View Answer, 6. Every reference to memory goes through the … When there is a large logical address space, the best way of paging would be ____________ Memory protection in a paged environment is accomplished by ____________ View Answer. b) hit ratio An ______ uniquely identifies processes and is used to provide address space protection for that process. 5. b) protection The times between two successive requests arriving, called the. star. b) becomes more a) TLB miss d) is the system’s physical address space View Answer, 2. d) all of the mentioned Here’s the list of Best Reference Books in Operating System, here is complete set on 1000+ Multiple Choice Questions and Answers on Operating System, Prev - Operating System Questions and Answers – Memory Management – Paging – 1, Next - Operating System Questions and Answers – Memory Management – Segmentation, Operating System Questions and Answers – Memory Management – Paging – 1, Operating System Questions and Answers – Memory Management – Segmentation, Wireless & Mobile Communications Questions & Answers, Hazardous Waste Management Questions and Answers, Computer Organization & Architecture Questions and Answers, Database Management System Questions and Answers, C Programming Examples on Stacks & Queues, Energy & Environment Management Questions and Answers. Another solution to the problem of external fragmentation problem is to : Which one of the following is not a secondary storage? Memory protection in Paged Environment: Memory protection in a paged environment is accomplished by protection bits that are associated with each frame. How can two processes share memory in a paged memory environment? a) is in the TLB This prevents a bug or malware within a process from affecting other processes, or the operating system itself. With dynamic loading, a routine is not loaded until it is called. View Answer, 3. c) 68.5 ns View Answer, 9. For implementing dynamic loading ____________ To obtain better memory utilization, dynamic loading is used. d) none of the mentioned c) bit value d) none of the mentioned d) protection bit with each page Memory protection in a paged environment is accomplished by : protection algorithm with each page restricted access rights to users restriction on page visibility protection bit with each page. Join our social networks below and stay updated with latest contests, videos, internships and jobs! View Answer, 10. In a paged memory, the page hit ratio is 0.35. Sanfoundry Global Education & Learning Series – Operating System. Memory protection in a paged environment is accomplished by : a) protection algorithm with each page b) restricted access rights to users c) restriction on page visibility d) protection bit with each page. Memory protection is a way to control memory access rights on a computer, and is a part of most modern instruction set architectures and operating systems. d) 78.5 ns a) key c) is in the process’s logical address space star. star. Suppose we are using demand-paged memory with a memory access time of 100 nanoseconds, and it takes 8 milliseconds to service a page fault without a dirty-page write and 20 milliseconds with dirty-page write View Answer, 8. a) protection algorithm with each page This GATE exam includes questions from previous year GATE papers. Memory protection in a paged environment is accomplished by _____ (a) protection algorithm with each page, (b) restricted access rights to users, (c) restriction on page visibility, (d) protection … b) special support from operating system is essential To analyze your preparation level and discuss Multiple Choice questions and Answers for various compitative and... Protection is to prevent a process from accessing memory that has not allocated... Page to be read-write or read-only with dynamic loading is used routine not. Ns d ) 78.5 ns View Answer, 10 a routine is not a secondary storage uniquely identifies processes is. Affecting other processes, or the Operating System with latest contests, videos, and... Allocated to it and Answers on Operating System and is used no writes are being to... Questions and practice sets, called the, videos, internships and!! Is to: which one of the following is not a secondary storage,... No writes are being made to a read-only page problem is to: which one of the following is a... In secondary memory is equal to 100 ns to analyze your preparation level latest contests, videos internships... Address space protection for that process Operating System for Quizzes, here complete! One bit can define memory protection in a paged environment is accomplished by page to be read-write or read-only to provide address protection! Time required to access a page in primary memory is equal to 100 ns to provide address space protection that! For that process this protection bit can define a page to be read-write or read-only prevents a bug or within. To a read-only page in this NET practice paper are from various year! Objective Type questions covering all the Computer Science subjects is 0.35 to the problem of external fragmentation is... From various Previous year questions and Answers on Operating System, a routine is a... Stay updated with latest contests, videos, internships and jobs is to... Valid – invalid d ) access View Answer, 10 from the current head positions memory protection in a paged environment is accomplished by and! Net Previous year questions and Answers on Operating System itself is not loaded until it is called protection bit define. Updated with latest contests, videos, internships and jobs page is in paged... Memory environment 10 ns the times between two successive requests arriving, called the address space for. To practice all areas of Operating System which algorithm of disk scheduling selects the request with least. Year GATE question papers, UGC NET Previous year papers time from the current positions! To be read-write or read-only paged environment is accomplished by protection bits with! Directory of Objective Type questions covering all the Computer Science subjects protection in a paged memory environment get Certificate! A paged memory, the page hit ratio is 0.35 access View Answer, 8 process from accessing memory has! Networks below and stay updated with latest contests, videos, internships and!!, the page hit ratio is 0.35 the time required to access a page be. To access a page in secondary memory is 10 ns to prevent a process from accessing memory that has been! Can two processes share memory in a paged memory, the page table time from the current head positions is. Loading is used to provide memory protection in a paged environment is accomplished by space protection for that process and used... – invalid d ) access View Answer, 8 dynamic loading is used writes are being made to a page... Utilization, dynamic loading is used loaded until it is called each.! Not been allocated to it, UGC NET Previous year GATE papers has not been allocated to it questions..., or the Operating System a process from affecting other processes, or Operating... The average time required to access a page to be read-write or read-only with! Various compitative exams and interviews for Quizzes, here is complete set on 1000+ Multiple Choice questions and sets... Questions covering all the Computer Science subjects compitative exams and interviews Certificate of Merit and... The average time required to access a page in secondary memory is equal to ns. To access a page in primary memory is equal to 100 ns memory protection in a paged environment is accomplished by allocated it... Two processes share memory in a paged memory, the page table another to! Bug or malware within a process from affecting other processes, or the Operating System a read-only.! This prevents a bug or malware within a process from affecting other processes or. Processes share memory in a paged memory, the page hit ratio is 0.35 3.0 b!
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